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A compound microscope has an objective of focal length 2 cm and eye piece of focal length 5 cm. An object is placed 2.4 cm in front of the objective. If the final image is at infinity, the magnifying power is ___

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Detailed Solution

$\frac{1}{v_{0}} - \frac{1}{u_{0}} = \frac{1}{f_{0}} \Rightarrow \frac{1}{v_{0}} + \frac{1}{2.4} = \frac{1}{2} \Rightarrow v_{0} = 12$

$m = \frac{v_{0}}{u_{0}} \frac{D}{f e}$

$m = \frac{12}{2.4} \times \frac{25}{5} = 25$

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