A compound on analysis was found to contain $53.33 % C, 15.5 % H$ and the rest nitrogen. The formula of the compound is

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$C_{3} H_{7} N$

$C_{2} H_{7} N$

$C_{4} H_{10} N$

$C_{2} H_{8} N$

answer is B.

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Detailed Solution

Let the compound be 100g this means that it has 53.33g carbon,15.5g hydrogen( $H$ ), 31.17g nitrogen now calculating moles for them we get 4.4,15.5 and 2.2 respectively.

Now dividing all moles by 2.2 since being smallest we approximately get 2,7,1.

Hence the compound is $C_{2} H_{7} N$ .

Hence option B is the correct answer.

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