A compound related to acetylacetone is 1,1,1-trifluoro-acetyl acetone (abbreviated Hffa) ${\text{CF}}_{\text{3}}{\text{COCH}}_{\text{2}}{\text{COCH}}_{\text{3}}.$It forms complexes in a manner similar to acetylacetone. Both ${\text{Be}}^{\text{2}+}$and $C{u}^{2+}$form complexes with $ff{a}^{-}$ halving formula $M{\left(ffa\right)}_2$. Regarding these complexes the correct statements is/are

$B{e}^{2+}$ Complex is tetrahedral can exhibit optical isomerism as is do not possess plane of symmetry $C{u}^{2+}$ complex is square planar and it can exhibit geometrical isomerism. $B{e}^{2+}$ complex is diamagnetic and colourless where as $C{u}^{2+}$ complex is paramagnetic and coloured since Cu isi in +2 oxidation state with $d^9$ configuration

Note the dotted line indicates a bond pointing into the plane of paper, and the wedge indicates a bond pointing out of the plane of paper

Geometrical isomers of $Cu{\left(t+a\right)}_2$ are