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A compound slab is made of two parallel plates of copper and brass of the same thickness and having thermal conductivities in the ratio 4 : 1. The free face of copper is at $0^{0} C$ . The temperature of the internal is $20^{0} C$ . What is the temperature of the free face of brass?

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$0^{0} C$

$20^{0}$

$40^{0} C$

$100^{0} C$

answer is D.

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Detailed Solution

$\frac{Q}{t} = \frac{4 KA (20 - 0)}{d} = \frac{KA (θ - 20)}{d}$

or $80 = θ - 20 or θ = 100^{0} C$

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