A compound X, of boron reacts with NH₃ on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF₃with lithium aluminium hydride. The compounds X and Y are represented by the formulas

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B₂H₆, B₃N₃H₆

B₃N₃H₆, B₂H₆

BF₃, B₃N₃H₆

B₂O₃, B₃N₃H₆

answer is A.

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Detailed Solution

A compound X, of boron, reacts with NH₃ on heating to give another compound Y which is called inorganic benzene.

$\underset{X (Diborane)}{3 B_{2} H_{6}} + 6 {NH}_{3} \to 3 {[{BH}_{2} {({NH}_{3})}_{2}]}^{+} {[{BH}_{4}]}^{-}$

$3 {[{BH}_{2} {({NH}_{3})}_{2}]}^{+} {[{BH}_{4}]}^{-} \overset{∆}{\to} \underset{Y (Borazole / Inorganic benzene)}{2 B_{3} N_{3} H_{6}} + 12 H_{2}$

$4 {BF}_{3} + 3 {LiAlH}_{4} \to \underset{X}{2 B_{2} H_{6}} + 3 LiF + 3 {AlF}_{3}$

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