A compound X of the formula ${\mathrm{C}}_2{\mathrm{H}}_6\mathrm{O},$ on reaction with Na metal gave Y, X also reacts with ${\mathrm{PCl}}_5$ to give Z. The product obtained in the reaction between Y and Z is

The compound X, Y and Z are ethanol (C₂​H₅​OH), sodium ethoxide (C₂​H_5​ONa) and ethyl chloride (C₂​H₅​Cl) respectively.

Ethanol reacts with Na metal to form sodium ethoxide.

$\underset{\mathrm{X}}{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}}+\mathrm{Na}\to \underset{\mathrm{Y}}{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{ONa}}+\frac{1}{2}{\mathrm{H}}_2$

Ethanol also reacts with PCl₅​ to give ethyl chloride.

$\underset{\mathrm{X}}{ {\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}}+{\mathrm{PCl}}_5\to \underset{\mathrm{Z}}{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Cl}}$

Diethyl ether forms when sodium ethoxide (Y) and ethyl chloride (Z) react with each other.

 $\underset{\mathrm{Y}}{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{ONa}}+\underset{\mathrm{Z}}{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Cl}}\to {\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{OC}}_2{\mathrm{H}}_5+\mathrm{NaCl}$