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Q.

A concave lens forms an image of an object placed 20 cm away from it at a distance of 20 cm on the other side of the lens. If the object is moves 5 cm toward the lens, the image will be

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a

5 cm towards the lens

b

5 cm away from the lens

c

10 cm towards the lens

d

10 cm away from the lens

answer is D.

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Detailed Solution

$\begin{array}{l} clearly, 2 f = 20 cm \\ or f = 10 cm \\ Now, u = - 15 cm, v = ? \\ f = 10 cm \\ \frac{1}{v} - \frac{1}{- 15} = \frac{1}{10} or \\ \frac{1}{v} + \frac{1}{15} = \frac{1}{10} or \\ \frac{1}{v} = \frac{1}{10} - \frac{1}{15} . or \\ \frac{1}{v} = \frac{3 - 2}{30} = \frac{1}{30} or \\ v = 30 cm \end{array}$

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