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A concave lens of focal length 1/3 m forms a real, inverted image twice in size of the object. The distance of the object from the lens is

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0.33 m

0.5 m

1 m

0.166 m

answer is A.

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Detailed Solution

$\begin{array}{l} m = \frac{f}{f + u} \\ - 2 = \frac{\frac{1}{3}}{\frac{1}{3} + u} \\ - \frac{2}{3} - 2 u = \frac{1}{3} or \\ - 2 u = \frac{1}{3} + \frac{2}{3} = 1 or \\ u = - \frac{1}{2} m = - 0 .5 m \end{array}$

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