Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

A concave lens of focal length $15 cm$ forms an image $10 cm$ from the lens. The image formed

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

inverted

erect

virtual

none of these

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The image formed is erect.
Given,
Image distance,

v = - 10 cm

and focal length,

f = - 15 cm

.
Form the lens formula,

\frac{1}{f} = \frac{1}{v} - \frac{1}{u}

Where

f

v

, and

u

are the focal length, image distance, and object distance, respectively.
On arranging the terms we get

\frac{1}{u} = \frac{1}{v} - \frac{1}{f}

On substituting the given values, we get the object distance as

\Rightarrow \frac{1}{u} = \frac{1}{(- 10)} - \frac{1}{(- 30)}

\Rightarrow u = - 30 cm

Hence, the distance of the object should be

- 30 cm

.
It is known that the magnification

(m)

produced is the ratio of the image distance

(v)

to the object distance

(u)

. It can also be defined as the ratio of the image height

(h')

to the object height

(h)

. Mathematically,

m = \frac{v}{u} = \frac{h'}{h}

On substituting the given values, we get the magnification

(m)

\Rightarrow m = \frac{v}{u}

\Rightarrow m = \frac{- 10}{- 30}

\Rightarrow m = 0.33

Hence, the magnification for the image formed is

0.33 ModerateFormula basedApplication

.
The positive sign indicates that the image formed is erect.
$Question Image$

Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!