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A concave mirror has a focal length of 16.2 cm, and a 4 cm tall light bulb is placed at a distance of 8.1 cm from the mirror. The distance of the image from the mirror is ____________.

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16.2 cm

17.85 cm

16.5 cm

20 cm

answer is A.

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Detailed Solution

Object distance u = - 8.1 cm

Focal length f = -16.2 cm

By, Mirror Formula, we have 1/f = 1/u + 1/v

$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$

$\frac{1}{v} = \frac{1}{(- 16.2)} - \frac{1}{(- 8.1)}$

$\frac{1}{v} = \frac{- 1}{16.2} + \frac{1}{8.1}$

$V = \frac{- 1 + 2}{16.2} = \frac{1}{16.2}$

$V = 16.2 cm$

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