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A concave mirror has radius of curvature of 24 cm. The distance of an object from the mirror if an image is formed which is virtual and 3 times the size of the object is

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a

4 cm

b

6 cm

c

8 cm

d

10 cm

answer is C.

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Detailed Solution

$R = - 24 cm; v = - 3 u; f = - 12 cm \begin{array}{l} \frac{1}{f} = \frac{1}{v} + \frac{1}{u} = \frac{- 1}{12} = \frac{- 1}{3 u} + \frac{1}{u} = \frac{- u + 3 u}{3 u^{2}} = \frac{2 u}{3 u^{2}} \\ - 3 u = 2 \times 10 \\ u = \frac{- 24}{3} = - 8 cm \\ u = 8 cm \end{array}$

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