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A concave mirror having radius of curvature 40 cmis placed in front of an illuminated point source at a distance of 30 cm from it. Then the location of the image is

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60 cm from the mirror on the same side of the object

30 cmfrom the mirror on the opposite side of the object

30 cmfrom the mirror on the same side of the object

60 cm from the mirror on the opposite side of the object

answer is B.

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Detailed Solution

$R = - 40 cm$

$f = \frac{R}{2} = \frac{- 40}{2} = - 20 cm$

$u = - 30 cm$

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$

$\frac{- 1}{20} = \frac{- 1}{30} + \frac{1}{v}$

$\frac{1}{v} = \frac{- 1}{20} + \frac{1}{30}$

$\frac{1}{v} = \frac{- 30 + 20}{600}$

$\frac{1}{v} = \frac{- 10}{600}$

$v = - 60 cm$

$v = 60 cm and image is formed at same side of object$

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