A concave mirror having radius of curvature 40 cmis placed in front of an illuminated point source at a distance of 30 cm from it. Then the location of the image is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

60 cm from the mirror on the same side of the object

30 cmfrom the mirror on the opposite side of the object

30 cmfrom the mirror on the same side of the object

60 cm from the mirror on the opposite side of the object

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$R = - 40 cm$

$f = \frac{R}{2} = \frac{- 40}{2} = - 20 cm$

$u = - 30 cm$

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$

$\frac{- 1}{20} = \frac{- 1}{30} + \frac{1}{v}$

$\frac{1}{v} = \frac{- 1}{20} + \frac{1}{30}$

$\frac{1}{v} = \frac{- 30 + 20}{600}$

$\frac{1}{v} = \frac{- 10}{600}$

$v = - 60 cm$

$v = 60 cm and image is formed at same side of object$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE