A concave spherical mirror has a radius of curvature of $50 c m$ . Find position(s) of an object for which the image is four times as large as the object.

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18.75 cm in front of mirror

12.25 cm in front of mirror

12.25 cm behind mirror

31.25 cm in front of mirror

answer is A, B.

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Detailed Solution

$m = \pm 4 . S o |v| = 4 |u| F o r r e a l i m a g e, \frac{1}{(- 4 u)} + \frac{1}{(- u)} = \frac{1}{- 25} \Rightarrow u = 31.25 c m F o r v i r t u a l i m a g e, \frac{1}{+ 4 u} + \frac{1}{(- u)} = \frac{1}{(- 25)} \Rightarrow u = 18 75 c m$

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