A condenser of capacity 16 mF(C₁ )charged to a potential of 20V is connected to a condenser of capacity C (C₂)charged to a potential of 10 V as shown in the figure. If the common potential is 14 V, the capacity C is equal to

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8 mF

4 mF

18 mF

24 mF

answer is D.

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Detailed Solution

$V_{c} = \frac{C_{1} V_{1} - C_{2} V_{2}}{C_{1} + C_{2}}; 14 = \frac{16 \times 10^{- 3} \times 20 - C \times 10}{16 \times 10^{- 3} + C}$
$24 C = 96 \times 10^{- 3} \Rightarrow C = 4 mF$

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