A condenser of capacity C₁ is charged to a potential V. The electrostatic energy stored in it is U₀. It is connected to another uncharged condenser of capacity C₂ in parallel. The energy dissipated in process is

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$(\frac{C_{1}}{C_{1} + C_{2}}) U_{0}$

$(\frac{C_{2}}{C_{1} + C_{2}}) U_{0}$

$(\frac{C_{1} C_{2}}{2 (C_{1} + C_{2})}) U_{0}^{2}$

$(\frac{C_{1} - C_{2}}{C_{1} + C_{2}}) U_{0}$

answer is A.

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Detailed Solution

$\begin{array}{l} U_{0} = \frac{1}{2} C_{1} V^{2}; ΔU = \frac{1}{2} \frac{C_{1} C_{2}}{C_{1} + C_{2}} V^{2} = \frac{C_{2}}{C_{1} + C_{2}} (\frac{1}{2} C_{1} V^{2}) \\ ΔU = \frac{C_{2} U_{0}}{C_{1} + C_{2}} \end{array}$

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