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Q.

A conductance cell was filled with a $0.02 M K C l$ solution which has a specific conductance of $2.768 \times 10^{- 3} o h m^{- 1} c m^{- 1}$ . If its resistance is 82.4 ohm at $25^{0} C$ , the cell constant is :

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a

$0.2821 c m^{- 1}$

b

$0.2182 c m^{- 1}$

c

$0.2281 c m^{- 1}$

d

$0.2381 c m^{- 1}$

answer is B.

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Detailed Solution

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$\begin{array}{l} R = ρ (\frac{l}{A}) \\ 82.4 = (\frac{1}{2.768}) \times 10^{3} [\frac{l}{A}] \\ \frac{l}{A} = 0.2281 \end{array}$

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A conductance cell was filled with a 0.02 M KCl solution which has a specific conductance of 2.768×10−3 ohm−1 cm−1 . If its resistance is 82.4 ohm at 250C , the cell constant is :