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Q.

A conductance cell was filled with a 0.02 M KCl    solution which has a specific conductance of 2.768×10−3 ohm−1 cm−1   . If its resistance is 82.4 ohm at  250C , the cell constant is :

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a

0.2821 cm−1

b

0.2182 cm−1

c

0.2281 cm−1

d

0.2381 cm−1

answer is B.

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Detailed Solution

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R=ρ(lA)82.4=(12.768)×103[lA]lA=0.2281

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