A conducting circular loop is in a perpendicular magnetic field of induction 10^–2 T. If the radius of the loop starts shrinking at a uniform rate of 1 mm/s, then the e.m.f. induced in the loop at the instant when its radius is 10 cm will be

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

2µV

2πµV

πµV

1µV

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$\begin{array}{l} E = \frac{dϕ}{dt}; E = \frac{d}{dt} ({Bπr}^{2}); E = Bπ 2 r \frac{dr}{dt} \\ E = 10^{- 2} \times π \times 2 \times 10^{- 1} \times 10^{- 3}; E = 2 πμv \end{array}$

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!