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A conducting circular loop is in a perpendicular magnetic field of induction 10^–2 T. If the radius of the loop starts shrinking at a uniform rate of 1 mm/s, then the e.m.f. induced in the loop at the instant when its radius is 10 cm will be

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2µV

2πµV

πµV

1µV

answer is D.

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Detailed Solution

$\begin{array}{l} E = \frac{dϕ}{dt}; E = \frac{d}{dt} ({Bπr}^{2}); E = Bπ 2 r \frac{dr}{dt} \\ E = 10^{- 2} \times π \times 2 \times 10^{- 1} \times 10^{- 3}; E = 2 πμv \end{array}$

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