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A conducting circular loop is placed in a uniform magnetic field 0.04T with its plane perpendicular to the magnetic field. The radius of the loop starts sinking at 2 mm/s The induced emf in the loop when the radius is 2 cm is:

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$3 .2 π μV$

$1.6 π μV$

$4 .8 π μV$

$0 .8 π μV$

answer is B.

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Detailed Solution

$ε = - \frac{dϕ}{dt} = - NB \frac{dA}{dt}$

$\begin{array}{l} ε = NB 2 πr \frac{dr}{dt} \\ = 1 \times 0.04 \times 2 π \times 2 \times 10^{- 3} \times 2 \times 10^{- 2} \\ = 32 π \times 10^{- 7} \\ = 3.2 π μV \end{array}$

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