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Q.

A conducting circular loop is placed in a uniform magnetic field 0.04 T with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at 2mm/s. The induced emf in the loop when the radius is 2 cm is

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a

$0.8 π μ V$

b

$4.8 π μ V$

c

$3.2 π μ V$

d

$1.6 π μ V$

answer is D.

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Detailed Solution

$e m f = | e | = \frac{d ϕ}{d t} = B π (2 r) \frac{d r}{d t}$

$= 0.04 \times π \times 2 \times 2 \times 10^{- 2} \times 2 \times 10^{- 3}$

$= 3.2 π μ V$

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