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Q.

A conducting circular loop of radius $\frac{10}{\sqrt{π}} c m$ is placed perpendicular to a uniform magnetic field of 0.5 T. The magnetic field is decreased to zero in 0.5 s at a steady rate. The induced emf in the circular loop at 0.25 s is:

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a

emf = 10 mV

b

emf = 100 mV

c

emf = 1 mV

d

emf = 5 mV

answer is D.

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Detailed Solution

$e = - \frac{Δ ϕ}{Δ t} = \frac{(B_{i} - B_{f}) A}{Δ t}$
$= \frac{(0.5 - 0)}{0.5} π [\frac{10 \times 10^{- 2}}{\sqrt{π}}] = 10^{- 2} V = 10 m v$

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