A conducting circular loop of radius $\frac{10}{\sqrt{π}}$ cm is placed perpendicular to a uniform magnetic field of $0.5 T$ . The magnetic field is decreased to zero in $0.5 s$ at a steady rate. The induced emf in the circular loop at $0.25 s$ is :

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emf = 10mV

emf = 1mV

emf = 100mV

emf = 5mV

answer is D.

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Detailed Solution

$\begin{array}{l} e = - \frac{Δ \emptyset}{Δt} = \frac{(B_{i} - B_{f}) A}{Δt} \\ = \frac{(0.5 - 0)}{0.5} π {[\frac{10 \times 10^{- 2}}{\sqrt{π}}]}^{2} \end{array}$
= 10^-2 V = 10mV

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