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A conducting ring of mass 4kg, radius 0.5m carries a current of 2A. It is placed on a smooth horizontal surface. When a horizontal magnetic field of 10 T parallel to the diameter of the ring is applied, the initial acceleration is (in rad/sec²)

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5π

20π

40π

10π

answer is D.

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Detailed Solution

$n i A B = I α {niπr}^{2} B = \frac{{Mr}^{2}}{2} α α = \frac{2 niπB}{M} here n = 1, i = 2 A, M = 4 kg, B = 10 T substituting α = 10 π rad / \sec^{2}$

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