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Q.

A conducting ring of radius R & mass 300 g, carrying current I ampere as shown in the figure. A bar magnet with its north pole up is placed along the symmetric axis below the conducting ring at a distance of 2m from the centre of ring. At the location of ring, the magnetic field makes an angle 300 with vertical and its magnitude is 13π Tesla. If ring remains at rest in its position, find the product of current I in the ring and radius R of ring in ampere-meter (g=10m/s2).  

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answer is 9.

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Detailed Solution

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Fmag=mg(Bsin300)×I×(2πR)=mgIR=mg2πBsin300=0.3×10×3π×22π=9Am

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