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A conducting rod AB of length l = 1 m is moving at a velocity $υ = 4 m/s$ making an angle $30°$ with its length. A uniform magnetic field B = 2T exists in a direction perpendicular to the plane of motion. Then

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V_{A} - V_{B} = 8 V

V_{A} - V_{B} = 4 V

V_{B} - V_{A} = 8 V

V_{B} - V_{A} = 4 V

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detailed solution

Correct option is B

$V_{A} - V_{B} = B l V \sin θ$

$2 = 2 \times 1 \times 4 \times \frac{1}{2} = 4 volts$

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A conducting rod AB of length l = 1 m is moving at a velocity υ=4 m/s making an angle 30° with its length. A uniform magnetic field B = 2T exists in a direction perpendicular to the plane of motion. Then

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Ready to Test Your Skills?

free study material

A conducting rod AB of length l = 1 m is moving at a velocity $υ = 4 m/s$ making an angle $30°$ with its length. A uniform magnetic field B = 2T exists in a direction perpendicular to the plane of motion. Then