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A conducting rod AB of length l = 1 m is moving at a velocity υ=4m/s making an angle 30° with its length. A uniform magnetic field B = 2T exists in a direction perpendicular to the plane of motion. Then

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By Expert Faculty of Sri Chaitanya
a
VAVB=8V
b
VAVB=4V
c
VBVA=8V
d
VBVA=4V

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detailed solution

Correct option is B

VAVB=BlVsinθ

2=2×1×4×12=4volts


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