A conducting rod AB of length l = 1 m is moving at a velocity υ=4 m/s making an angle 30⁰ with its length. A uniform magnetic field B = 2T exists in a direction perpendicular to the plane of motion. Then 
 

Given data:

Rod of length l=1m

Velocity of the rod v=4m/s

Magnetic field B=2T

Length of the rod and velocity makes an angle 30⁰

Concept used: Magnetic fields

Detailed solution:

We know that potential difference ${\mathrm{V}}_{\mathrm{A}}-{\mathrm{V}}_{\mathrm{B}}=\mathrm{Blv} \mathrm{sin\theta }$

Induced current flows from B to A which implies that V_A>V_B

   ${\mathrm{V}}_{\mathrm{A}}-{\mathrm{V}}_{\mathrm{B}}$=$\left(2\right)\left(1\right)\left(4\right)\left(Sin30\right)$

   ${\mathrm{V}}_{\mathrm{A}}-{\mathrm{V}}_{\mathrm{B}}$=4V