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Q.

A conducting rod of length 2l is rotating with constant angular speed $ω$ about its perpendicular bisector. A uniform magnetic field $\vec{B}$ exists parallel to the axis of rotation. The emf induced between two ends of the rod is

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a

zero

b

$\frac{1}{8} B ω l^{2}$

c

$\frac{1}{2} B ω l^{2}$

d

$B ω l^{2}$

answer is D.

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Detailed Solution

$e = \int_{- ℓ / 2}^{ℓ / 2} Bωrdr = 0$

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