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Q.

A conducting rod of length 2l is rotating with constant angular speed ω about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. The emf induced between two ends of the rod is

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a

zero

b

18Bωl2

c

12Bωl2

d

Bωl2

answer is D.

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Detailed Solution

e=/2/2Bωrdr=0

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