Q.

A conducting rod PQ of length 1m is moving with uniform velocity of 2m/s in a uniform magnetic field of 2T directed into the plane of paper. A capacitor of capacity C=10μF is connected as shown. Then
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a

qA=40μC,qB=+40μC

b

qA=qB=0

c

qA=+40μC,qB=40μC

d

qA=+40μC,qB=+40μC

answer is B.

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Detailed Solution

einduced =Blv=4V
Q=Ceinduced 

Q=40μC
Apply right hand rule to know direction of induced current

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A conducting rod PQ of length 1m is moving with uniform velocity of 2m/s in a uniform magnetic field of 2T directed into the plane of paper. A capacitor of capacity C=10μF is connected as shown. Then