A conducting rod PQ of length L = 1 m is moving with a uniform speed v = 2.0 m s^-1 in a uniform magnetic field B = 4.0 T directed into the plane of the paper.
A capacitor of capacity $C = 10 μ F$ is connected as shown in figure, then

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$q_{A} = - 80 μ C a n d q_{B} = + 80 μ C$

charge stored in the capacitor increases exponentially with time

$q_{A} = + 80 μ C a n d q_{B} = - 80 μ C$

$q_{A} = 0 = q_{B}$

answer is A.

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Detailed Solution

q =CV=C(Bvl)
= (10 x 10^-6) (4) (2) (1)
$= 80 μ C = c o n s \tan t$
Magnetic force on the electron in the conducting rod PQ is towards Q.Therefore, A is positively charged and B is negatively charged.

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