A conducting sphere of radius b has a spherical cavity with its center displaced by “a” from center of sphere. A point charge q is placed at the center of cavity. ‘Q’ charge is given to conducting sphere and charge $q_{0}$ is placed at a distance c from center $(O_{1})$ of sphere such that $O_{1}, O_{2}$ and P are collinear.

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Potential of conductor is $(\frac{q_{0}}{4 π ε_{0} c} + \frac{Q + q}{4 π ε_{0} b})$

Charge distribution on inner surface of cavity is uniform

Intensity of electric field at $O_{1}$ is $\frac{1}{4 π \in_{0}} \frac{q_{0}}{c^{2}}$

Charge distribution of outer surface of conducting sphere is non uniform

answer is A, B, C.

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Detailed Solution

Charge distribution on inner surface is uniform and non-uniform on outer surface, as the charge q is placed at the center of the cavity.

$V_{c e n t e r} = V_{c o n d u c t o r}$

$= \frac{k (Q + q)}{b} + \frac{k q_{0}}{c}$

Charge distribution of outer surface of conducting sphere is non uniform as the charge q0 is not placed symmetric to the sphere.

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