A conducting sphere of radius b has a spherical cavity with its center displaced by “a” from center of sphere. A point charge q is placed at the center of cavity. ‘Q’ charge is given to conducting sphere and charge $q_{0}$ is placed at a distance c from center $(O_{1})$ of sphere such that $O_{1}, O_{2}$ and P are collinear.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

Potential of conductor is $(\frac{q_{0}}{4 π ε_{0} c} + \frac{Q + q}{4 π ε_{0} b})$

Charge distribution on inner surface of cavity is uniform

Intensity of electric field at $O_{1}$ is $\frac{1}{4 π \in_{0}} \frac{q_{0}}{c^{2}}$

Charge distribution of outer surface of conducting sphere is non uniform

answer is A, B, C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Charge distribution on inner surface is uniform and non-uniform on outer surface, as the charge q is placed at the center of the cavity.

$V_{c e n t e r} = V_{c o n d u c t o r}$

$= \frac{k (Q + q)}{b} + \frac{k q_{0}}{c}$

Charge distribution of outer surface of conducting sphere is non uniform as the charge q0 is not placed symmetric to the sphere.

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE