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A conducting sphere of radius R carrying a charge Q lies inside an uncharged conducting shell of radius 2R. If they are joined by a metal wire

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Charge $\frac{Q}{3}$ will flow from sphere to shell

Charge $\frac{2 Q}{3}$ will flow from sphere to shell

Charge Q will flow from sphere to shell

$\frac{Q^{2}}{16 π ε_{0} R}$ amount of heat will be produced

answer is D, C.

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Detailed Solution

At t=0 S is charge

Entire charge comes to surface
Initial energy= $\frac{K Q^{2}}{2 R}$
Final energy = $\frac{K Q^{2}}{2 (2 R)}$
$Δ U = \frac{K Q^{2}}{4 R} = \frac{Q^{2}}{16 π \in_{0} R}$

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