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A conducting sphere of radius R has two spherical cavities of radius a and b. The cavities have charges q_a & q_b respectively at their centers. ‘A’ is the center of the sphere and ‘B’ is the center of the cavity of radius ‘b’. Find: electrical potential at r (distance from A) which is greater than R,

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$\frac{K (q_{a} + q_{b})}{r}$

$\frac{K (q_{a} - q_{b})}{r}$

$\frac{K (- q_{a})}{r}$

$\frac{K (q_{a})}{r}$

answer is B.

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Detailed Solution

To find electrical potential outside shell, total charge is assumed to be at center.

$V_{r} = \frac{K (q_{a} + q_{b})}{r}$

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