A conducting spherical shell is earthed, A positive charge +q₁ is placed at the center and another small positive charge +q₂ is placed at a distance r from q₁ (as shown in the figure). Ignore the effect of induced charge due to q₂ on the sphere. Then the coulomb force on q₂ is

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$\frac{q_{1} q_{2}}{4 {πε}_{0} (r - R)^{2}}$

$\frac{q_{1} q_{2}}{4 {πε}_{0} r^{2}}$

$\frac{q_{1} q_{2}}{4 {πε}_{0} (r^{2} - R^{2})}$

Zero

answer is A.

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Detailed Solution

As the sphere is grounded, the charge on the inner surface will be -q₁ and the charge on the outer surface will be zero

There is no charge on the outer surface. Hence, no force on q₂ (figure). Question Image

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