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Q.

A conducting square loop of length ‘L’ is placed in a magnetic field of Induction B₀. End ‘A’ and End ‘C’ are moved away from each other. So that finally the square loop becomes a straight line. The total charge flowing through the loop, if its resistance is ‘R’ then :

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a

$\frac{B_{0} L^{2}}{R}$

b

$> \frac{B_{0} L^{2}}{R}$

c

$\frac{B_{0} L^{2}}{πR}$

d

$< \frac{B_{0} L^{2}}{R}$

answer is C.

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Detailed Solution

$Q = \frac{φ_{i} - φ_{f}}{R} = \frac{L^{2} B_{0}}{R}$

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A conducting square loop of length ‘L’ is placed in a magnetic field of Induction B0. End ‘A’ and End ‘C’ are moved away from each other. So that finally the square loop becomes a straight line. The total charge flowing through the loop, if its resistance is ‘R’ then :