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Q.

A conducting square loop of side L and resistance R moves in its plane with a uniform velocity υ perpendicular to one of its sides. A magnetic induction B, constant in time and space, pointing perpendicular to and into the plane of the loop exists everywhere. The current induced in the loop is 

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a

zero

b

BLυ/R clockwise

c

BLυ/R anticlockwise

d

2BLυ/R anticlockwise

answer is D.

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Detailed Solution

The magnetic flex passing through the square loop of side L placed in a magnetic field normal to its plane is ϕ=BA=BA=BL2. The flux through the loop does not change with time. By Faraday’s law, induced emf   e=dϕ/dt=0 and hence the induced current  i=e/R=0.

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