In the given question magnetic field directed into the paper is increasing at a constant rate. 

\therefore Induced current should produce a magnetic field directed out of the paper. Thus current in both loops must be anticlockwise. 

Induced emf on right side of loop will be more as area of its loop on right side is more.

$\left[\because e=-\frac{d\varphi }{dt}=-A\frac{dB}{dt}\right]$

$e\propto A$

Hence the net current induced in the complete loop will be along $DCBAD$. Therefore the answer is $\left(4\right)$.