A conducting wire is bent in the form of a semicircle of radius 5 cm. At the center of the semicircle it produces a magnetic induction field of $2 π \times 10^{- 6} T$ , the current through the wire is

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Detailed Solution

$\begin{array}{l} Bc = \frac{μ_{0} i}{4 r} = \frac{4 π \times 10^{- 7} \times i}{4 \times 5 \times 10^{- 2}} \\ 2 π \times 10^{- 6} = \frac{4 π \times 10^{- 7} \times i}{4 \times 5 \times 10^{- 2}} \Rightarrow i = 1 A \end{array}$

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