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A conductor 30 cm long and has resistance $2 Ω$ moves at a uniform speed of 5 m/s at right angles to a uniform magnetic field of flux density 1.25 T. Determine the ratio of current flowing in the conductor when its ends are connected with a load of 2 ohm and its ends are connected to a load of 6 ohm.

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Detailed Solution

Induced emf $E = B l v$ is same for both cases.

Therefore $i α 1 / R_{e f f}$

$\frac{i_{1}}{i_{2}} = \frac{r_{2}}{r_{1}} = \frac{6 + 2}{2 + 2} = 4$

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