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A conductor consists of a circular loop of radius $R = 10 c m$ and two straight long sections as shown in the figure. the wire lies in the plane of the paper and carries a current of $i = 7.00 A$ . Determine the magnitude direction of the magnetic field at the entre of the loop.

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$B = - 5.8 \times 10^{- 5} T$

$B = 5.8 \times 10^{- 5} T$

$B = 5.9 \times 10^{- 5} T$

$B = 5.8 \times 10^{- 4} T$

answer is B.

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Detailed Solution

Both straight and circular wires will produce magnetic field inwards.

$∴ B = \frac{μ_{0} i}{2 πR} + \frac{μ_{0} i}{2 R} = \frac{(2 \times 10^{- 7}) (7)}{0.1} + \frac{(4 π \times 10^{- 7}) (7)}{2 \times 0.1} = 5.8 \times 10^{- 5} T$

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