A conductor moves with a velocity $12m/s$ at an angle of (i) ${90}^{\circ }$  (ii) ${30}^{\circ }$ to a magnetic field produced between two square faced poles of side length $2cm$ . When the flux leaving the pole face is $5\mu Wb$ . Which of the following statements are correct?

Flux through each face $\phi =5\mu$$wb$  
 $\Rightarrow B{\left(2\times {10}^{-2}\right)}^2=5\times {10}^{-6}$
 $\Rightarrow B=\frac{5}{2}\times {10}^{-2}T$
(i) Now a conductor moves at ${90}^0$  with  $\overline{B}$ emf induced =  

$B\mathcal{l}V=\frac{5}{4}\times {10}^{-2}\times 2\times {10}^{-2}\times 12=3mV$
(ii) The conductor moves at ${30}^0$  with  $\overline{B}$, hence velocity perpendicular to $\overline{B}$  is $V\sin {30}^0$  .
  $\therefore$ emf induced  $=B\mathcal{l}\left(V\sin {30}^0\right)=1.5mV$
There will be no induced emf due to velocity component $v\cos \theta =\frac{v}{2},\theta ={60}^0$ .
Hence the conductor moves at an angle of  ${60}^0$ to the magnetic field.