AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A conductor of length $65 cm$ has a resistance of $4 Ω$ . The resistance of the same conductor of length $260 cm$ is [[1]] $Ω$ .

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

A conductor of length

65 cm

has a resistance of

4 Ω

. The resistance of the same conductor of length

260 cm

16 Ω

.
Length of the silver wire

L_{1} = 65 cm

Resistance of the silver wire

R_{1} = 4 Ω

Length of the wire

L_{2} = 260 cm

Resistance of the wire

= R_{2}

R = (\frac{ρL}{A})

Where

ρ =

resistivity of the conductor,

L =

length of the conductor,

A =

area of cross-section of conductor
Resistance is directly proportional to the length of a conductor.
Therefore,

\frac{R_{1}}{R_{2}} = \frac{L_{1}}{L_{2}}

Substituting the values,

\Rightarrow \frac{4}{R_{2}} = \frac{65}{260}

\Rightarrow

R_{2} = \frac{260 \times 4}{65}

\Rightarrow R_{2} = 16 Ω

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!