Book Online Demo

Check Your IQ

Try Test

Courses

A conductor of length $65 cm$ has a resistance of $4 Ω$ . The resistance of the same conductor of length $260 cm$ is [[1]] $Ω$ .

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

A conductor of length

65 cm

has a resistance of

4 Ω

. The resistance of the same conductor of length

260 cm

16 Ω

.
Length of the silver wire

L_{1} = 65 cm

Resistance of the silver wire

R_{1} = 4 Ω

Length of the wire

L_{2} = 260 cm

Resistance of the wire

= R_{2}

R = (\frac{ρL}{A})

Where

ρ =

resistivity of the conductor,

L =

length of the conductor,

A =

area of cross-section of conductor
Resistance is directly proportional to the length of a conductor.
Therefore,

\frac{R_{1}}{R_{2}} = \frac{L_{1}}{L_{2}}

Substituting the values,

\Rightarrow \frac{4}{R_{2}} = \frac{65}{260}

\Rightarrow

R_{2} = \frac{260 \times 4}{65}

\Rightarrow R_{2} = 16 Ω

Watch 3-min video & get full concept clarity