AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A cone of radius $8 cm$ and height $12 cm$ is divided into two parts by drawing a plane through the midpoint of its axis and parallel to its base. What is the ratio of the volumes of the two parts?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

1: 7

6: 1

3: 2

2: 5

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Given that a cone of radius

8 cm

and height

12 cm

is divided into two parts.
We have the following formula,
Volume of cone =

13 π (r) 2 h

The volume of the original cone will be,

= 13 π (8) 2 (12) = 256 π

The height of the small cone will be,

= 122 = 6

The radius of the small cone will be,

= 82 = 4

Volume of the small cone will be,

= 13 π (4) 2 (6) = 32 π

Volume of the frustum =Volume of the original cone - Volume of the small cone

= 256 π − 32 π = 224 π

The ratio of the volume of the frustum to the volume of the small cone will be,

= 224 π : 32 π

=7:1
Thus, the ratio of the volumes of two parts is

7 : 1

.
Therefore the correct option is 2.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!