A conical party cap has a slant height of 18 cm. The perimeter of the base of the cap is 44 cm. The cap is to be covered with glossy paper. What is the area of the glossy paper required to cover the cap?

It is given that, the perimeter of the base of the cap = 44 cm

Let the radius of the circular base of the cap be r.

$\therefore 2\mathrm{\pi r}=44$

$\Rightarrow 2\times \frac{22}{7}\times \mathrm{r}=44$

$\Rightarrow \mathrm{r}=\frac{44\times 7}{2\times 22}=7 \mathrm{cm}$

The area of the glossy paper required to cover the cap is equal to the curved surface area of the cap.

Slant height (l) of the cap = 18 cm

Thus, the curved surface area of cap = πrl = $\frac{22}{7}\times 7\times 18=396$

Hence, the area of the glossy paper required to cover the cap is 396 cm².