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A conical pendulum of length 1 m makes an angle $θ = 45^{0}$ w.r.t Z-axis and moves in a circle in the XY plane. The radius of the circle is 0.4 m and its center is vertically below O. The speed of the pendulum, in its circular path, will be : (Take g=10ms^–2)

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0.4 m/s

2 m/s

0.2 m/s

4 m/s

answer is B.

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Detailed Solution

T sin θ = mv²/r
T cos θ = mg
tan θ = v²/rg
θ = 45^∘
v² = rg
υ = $\sqrt{rg} = \sqrt{0.4 \times 10} = 2 m / s$

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