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Q.

A constant current was passed through a solution of  AuCl4 ion between gold electrodes. After a period of 10.0 minutes, the increase in mass of cathode was 1.314g. The total charge passed through the solution is ____ × 102F. (Given atomic mass of Au=197)

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answer is 2.

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Detailed Solution

Moles of Au deposited  =1.314197
Equivalents of Au deposited = Equivalents of charge conducted
 =1.314×3197=charge  in  F                            =0.02001                            =2×102
As one equivalent charge is one faraday

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