A constant force acting on a body of mass 1 kg provides it a kinetic energy of 1800 J by the end of 5th second. If the body was initially at rest at the beginning of action of force, then magnitude of force is equal to ___ N.

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answer is 12.

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Detailed Solution

a = F/m
As force is constant so block is moving with constant acceleration
$S = \frac{1}{2} a t^{2} = F t^{2} / 2 m$
From work energy theorem
$W = Δ K E = \vec{F} \cdot \vec{S}$
$\frac{F^{2} t^{2}}{2 m} = K E$
$F = \sqrt{\frac{2 m K E}{t^{2}}} = \sqrt{\frac{2 \times 1 \times 1800}{25}} = 12 N$

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