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Q.

A constant force acts for 10 s on a stationary body of mass 10 kg after which the force ceases to act. The body moves a distance of 50 m in the next 5seconds. Find the magnitude of the force                          

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a

30 N

b

15 N

c

20 N

d

10 N

answer is A.

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Detailed Solution

It is moved with uniform speed after 10 s. The distance travelled in 5 s is 50 m

            u=0, t=10 s, m=10kg

                a=v−ut=10−010=1

                s=vt

                v=505=10 ms−1

                F=ma=10×1=10 N

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