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A constant force acts on a body of mass $0.9 kg$ at rest for $10 s$ . If the body moves a distance of $250 m$ , the magnitude of force is

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3 N

4.5 N

4 N

5 N

answer is A.

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Detailed Solution

A constant force acts on a body of mass

0.9 kg

at rest for

10 s

. If the body moves a distance of

250 m

. The magnitude of the force is

4.5 N

.
Given data in the problem,
Mass,

m = 0.9 kg

Time of rest,

t = 10 s

Distance,

s = 250 m

And the initial velocity,

u = 0

So, by using the below formula,

s = ut + \frac{1}{2} {at}^{2}

Where,

s = distance

u = initial velocity

a = uniform acceleration

t = time

\Rightarrow 250 = 0 \times 10 + \frac{1}{2} {\times a \times 10}^{2}

\Rightarrow a = \frac{250}{50}

\Rightarrow a = 5 m s^{- 2}

and we know that

Force = mass \times acceleration

\Rightarrow F = m \times a

\Rightarrow F = 0.9 \times 5

\Rightarrow F = 4.5 N

The magnitude of the force is

4.5 N

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