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A constant force acts on an object of mass 10 kg for a duration of 4 s. It increases the object’s velocity from 6 ms⁻¹ to 14 ms⁻¹. Find the magnitude of the applied force.

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5 N

20 N

10 N

30 N

answer is A.

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Detailed Solution

m = 10 kg
t = 4 s
u = 6 ms⁻¹
v = 14 ms⁻¹

F = ma

F = m (v - u)/t

F = 10 (14 - 6)/4

F = 20 N

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