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A constant force ‘F’ acts on a moving body along a smooth quarter circular arc of radius ‘R’ fixed on horizontal surface. Calculate the work done by force F from A to B

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If force F always points towards ‘B’, then work $^{'} F \sqrt{2} R'$

If force F always acts tangentially $' \frac{F R π}{2}'$

If force F always acts parallel to AB $^{'} F \sqrt{2} R'$

If force F always acts parallel to AB ‘Zero’

answer is A, B.

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Detailed Solution

Workdone by force from A to B

a) $W = F . s$ from fig $S = \sqrt{2} R, W = F \sqrt{2} R,$ it always point towards B

b) If force acts tangentialy $W = F . s$

where $s = \frac{π R}{2}, W = \frac{F π R}{2}$

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