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Q.

A constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at 0°C and 100°C, respectively. When the pressure reading is 60 cm of mercury, the temperature is

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a

15°C

b

25°C

c

12.5°C

d

40°C

answer is A.

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Detailed Solution

$t = \frac{(p_{t} - p_{0})}{(p_{100} - p_{0})} \times 100 ° C = \frac{(60 - 50)}{(90 - 50)} \times 100 ° C = 25 ° C$

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